The correct answer is:
28 cm

Explanation:

P A

&

PB

are the tangent to the circle with centre 'O'

C D

is a tangent to circle at E which intersects

P A

and

PB

in C & D respectively and

P A = 14 c m

Lengths drawn from an external point to a circle are equal.

∴

P A = PB = 14 c m

Now perimeter of

Δ PC D = PC + C D + P D

= PC + (CE + E D) + P D

{∵ C D = CE + E D}

= PC + (C A + D B) + P D

{∵ C A = CE D B = D E}

= (PC + C A) + (D B + P D)

= P A + PB

{PC + C A = P A D B + P D = PB}

= 14 c m + 14 c m

= 28 c m

Thus the perimeter of

Δ PC D = 28 c m