Class 9 Practice – Level 3 – Set 2 Areas of Parallelograms and Triangles Leave a Comment / By Gulam Hamza / September 19, 2024 Class 9 Practice – Level 3 – Set 2 Areas of Parallelograms and Triangles Total questions: 15 1. In a parallelogram PQRS. The Altitude corresponding to sides PQ and PS are respectively. 7 cm and 8 cm find PS, if PQ=10 cm. 12.46 cm 16.2 cm 8.75 cm 18.3 cm None 2. WXYZ is a parallelogram with XP⊥WZ and ZQ⊥WX. If WX = 8 cm, XP=8 cm and ZQ=2 cm, find YX. 2 cm 6 cm 4 cm 8 cm None 3. The base BC of triangle ABC is divided at D so that BD=$\displaystyle \dfrac{1}{2}$ DC. Area of △ABD= 1/2 of the area of △ABC 1/3 of the area of △ABC 1/4 of the area of △ABC 1/6 of the area of △ABC None 4. In △ABC,D is the mid-point of AB.P is any point of BC.CQ∥PD meets AB in Q. Then area of (△BPQ) is equal to 1/2 area of (△ABC) 3/2 area of (△ABC) 5/2 area of (△ABC) 1/4 area of (△ABC) None 5. In the figure, compute the area of quadrilateral ABCD. 82 cm² 114 cm² 90 cm² 154 cm² None 6. In the figure, ∠AOB=90°,AC=BC,OA=12 cm and OC=6.5 cm. Find the area of △AOB. 30 cm² 15 cm² 45 cm² 65 cm² None 7. BD is a median of a triangle ABC. F is a point on AB such that CF intersects BD at E and BE = ED. If BF = 5 cm, BA is equal to 5k then k is A 1 1 2 3 4 None 8. In a △ABC,E is the mid-point of median AD. Then area of ( △BED) is equal to k/4 times area of Δabc 4 3 2 1 None 9. ABC is a triangle in which D is the mid-point of BC and E is the mid-point of AD. Find the ratio of the area of △BED and area of △ABC. 1:3 1:1 1:2 2:3 None 10. The figure formed by joining the consecutive mid-points of any rhombus is always A rectangle. A rhombus A parallelogram A square None 11. In the given Figure, ABCD,DCFE and ABFE are parallelograms. then ar(ADE) = ar(BCF). Yes No None 12. In fig, ABCD is a parallelogram and BC is produced to a point Q such that AD=CQ. If AQ intersect DC at P, then ar(BPC)=ar(DPQ). True False None of these Can't say None 13. ABCD is a trapezium with AB∥DC. A line parallel to AC intersects AB at X and BC at Y. then ar(△ADX)=ar(△ACY) True False None 14. In fig, ar(DRC)=ar(DPC) and ar(BDP)=ar(ARC). then both the quadrilaterals ABCD and DCPR are trapeziums. Yes No None 15. The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB (produced) at Q and then parallelogram PBQR is completed (figure). Find ar(ABCD) : ar(PBQR). 1:1 2:3 1:2 2:1 None 1 out of 15 Time's up